How do you find the slant asymptote of $f(x) = (x^3 - 2x^2 +x - 4) / (x^2 +1)$ ?

Question

3903 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-21T11:03:13

See Finding asymptotes for a good concise explanation

First divide the denominator into the numerator.
Calculation

$f(x) = x-2 -(2/(x^2+1))$

Then the slant asymptote is $y = x-2$

How do you find the slant asymptote of f(x) = (x^3 - 2x^2 +x - 4) / (x^2 +1)f(x) = (x^3 - 2x^2 +x - 4) / (x^2 +1)?