How do you find the slant asymptote of $f(x)= (x^3 - 4x^2 + 2x - 6 )/( x +3)$ ?

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Answer 1 · 2015-12-11T06:03:16

Slant/oblique asymptote doesn't exist.

By definition- slant/oblique asymptote can only exist if the degree of the numerator is ONE more than the degree of the numerator.

How do you find the slant asymptote of f(x)= (x^3 - 4x^2 + 2x - 6 )/( x +3)f(x)= (x^3 - 4x^2 + 2x - 6 )/( x +3)?