How do you find the slant asymptote of $f (x) = \frac{x - 3}{x - 4}$ $f(x)=(x-3)/(x-4)$ ?

Question

1385 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-13T00:55:07

Since the highest exponent for both the numerator and denominator is the same (it's 1), there is no slant asymptote .

You will have a slant asymptote when the greatest exponent in the numerator exceeds the greatest exponent in the denominator by 1.

For example, the following function will have a slant asymptote:

$f (x) = \frac{x^{2} - 3}{x - 4}$ $f(x)=(x^2-3)/(x-4)$

Because the exponent $2$ $2$ exceeds $1$ $1$ by exactly 1 unit.

hope that helped

How do you find the slant asymptote of f(x)=(x-3)/(x-4)f(x)=x−3x−4f(x)=(x-3)/(x-4)?