How do you find the slope and intercept for $3 x + 6 y = - 9$ $3x+6y=-9$ ?

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Answer 1 · 2017-05-07T01:52:42

Slope is $- \frac{1}{2}$ $-1/2$ and $y$ $y$ -intercept is $- \frac{3}{2}$ $-3/2$ .

The slope intercept form of equation of a line is $y = m x + c$ $y=mx+c$ , where $m$ $m$ is slope and $c$ $c$ is it's intercept on $y$ $y$ axis.

Hence, we should convert any equation of a line to the form $y = m x + c$ $y=mx+c$ i.e. solve it for $y$ $y$ to get slope and $y$ $y$ -intercept.

Hence, we can write the equation $3 x + 6 y = - 9$ $3x+6y=-9$ as

$6 y = - 3 x - 9$ $6y=-3x-9$

or $y = - \frac{3}{6} x - \frac{9}{6}$ $y=-3/6x-9/6$

or $y = - \frac{1}{2} x - \frac{3}{2}$ $y=-1/2x-3/2$

Hence, slope is $- \frac{1}{2}$ $-1/2$ and $y$ $y$ -intercept is $- \frac{3}{2}$ $-3/2$ .

graph{3x+6y=-9 [-5, 5, -2.5, 2.5]}

How do you find the slope and intercept for 3x+6y=−93x+6y=-9?