How do you find the slope and intercept for $3y=4x-5$ ?

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Answer 1 · 2016-08-31T22:56:09

$4/3$ is slope of line and $-5/3$ is its intercept on $y$ -axis.

The slope intercept form of equation of a line is $y=mx+c$ , where $m$ is the slope of line and $c$ is its intercept on $y$ axis.

For this we write the value of $y$ in terms of $x$ and then coefficient of $x$ gives us slope and constant term gives us its intercept on $y$ -axis.

As we have $3y=4x-5$ ,

$y=4/3x-5/3$ , hence

$4/3$ is slope of line and $-5/3$ is its intercept on $y$ -axis.

Answer 2 · 2016-08-31T22:59:02

$m = 4/3 and c = -5/3$

Re-arrange the equation of the straight line into the form of:
$y = mx + c rarr "solve for y"$

$3y = 4x -5 " "div 3$

$y = 4/3x -5/3 larr$ this is slope intercept form!

$m = 4/3 and y-"intercept" (c) = -5/3$

How do you find the slope and intercept for 3y=4x-53y=4x-5?