How do you find the slope and intercept for #3y=4x-5#?

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Answer 1 · 2016-08-31T22:56:09

#4/3# is slope of line and #-5/3# is its intercept on #y#-axis.

The slope intercept form of equation of a line is #y=mx+c#, where #m# is the slope of line and #c# is its intercept on #y# axis.

For this we write the value of #y# in terms of #x# and then coefficient of #x# gives us slope and constant term gives us its intercept on #y#-axis.

As we have #3y=4x-5#,

#y=4/3x-5/3#, hence

#4/3# is slope of line and #-5/3# is its intercept on #y#-axis.

Answer 2 · 2016-08-31T22:59:02

# m = 4/3 and c = -5/3#

Re-arrange the equation of the straight line into the form of:
#y = mx + c rarr "solve for y"#

#3y = 4x -5 " "div 3#

#y = 4/3x -5/3 larr # this is slope intercept form!

# m = 4/3 and y-"intercept" (c) = -5/3#