How do you find the slope and intercept for $8 x - 2 y = 14$ $8x-2y=14$ ?

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Answer 1 · 2016-11-07T06:30:23

Slope $m = 4$ $m=4$
y-intercept $- 7$ $-7$
x-intercept $\frac{7}{4}$ $7/4$

Given -

$8 x - 2 y = 14$ $8x-2y=14$

It is in the form

$a x + b y = c$ $ax+by=c$

If a linear equation is in this form, then -

It slope is $\frac{- a}{b}$ $(-a)/b$

In our case, we shall use this formula

$m = \frac{- 8}{- 2} = 4$ $m=(-8)/(-2)=4$

To find the y-intercept put $x = 0$ $x=0$

$8 (0) - 2 y = 14$ $8(0)-2y=14$
$- 2 y = 14$ $-2y=14$
$y = \frac{14}{- 2} = - 7$ $y=14/(-2)=-7$

To find the x-intercept put $y = 0$ $y=0$

$8 x - 2 (0) = 14$ $8x-2(0)=14$
$8 x = 14$ $8x=14$
$x = \frac{14}{8} = \frac{7}{4}$ $x=14/8=7/4$

How do you find the slope and intercept for 8x−2y=148x-2y=14?