Question

How do you find the slope and intercept of `-10x+4y=0`?

Answer 1

`"slope "=5/2," intercept "=0`

Explanation:

`"the equation of a line in "color(blue)"slope-intercept form"` is.

`•color(white)(x)y=mx+b`

`"where m represents the slope and b the y-intercept"`

`"arrange "-10x+4y=0" into this form"`

`"add 10x to both sides"`

`cancel(-10x)cancel(+10x)+4y=0+10x`

`rArr4y=10x+0`

`"divide both sides by 4"`

`(cancel(4) y)/cancel(4)=10/4x+0`

`rArry=5/2x+0larrcolor(red)" in slope-intercept form"`

`rArr"slope "=5/2," y-intercept "=0`
graph{5/2x [-10, 10, -5, 5]}

Answer 2

Slope is `5/2` and y-intercept is `0`

Explanation:

`-10x +4y =0 or 4y =10x or y = 10/4x or y =5/2x`

The slope intercept form of a straight line is `y=mx+c` ,

where `m` is slope and `c` is y-intercept.

Comparing `y= 5/2x+0` with `y=mx+c` we get

Slope as `m=5/2` and y-intercept as `c=0`

graph{-10x+4y=0 [-10, 10, -5, 5]} [Ans]