How do you find the slope and intercept of $12x+4y-2=0$ ?

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Answer 1 · 2018-04-19T03:13:43

Slope $=m=-3$

$y-$ intercept $=b=1/2$

Solve the equation for $y:$

$12x+4y-2=0$

Add $2$ to both sides:

$12x+4y=2$

Subtract $12x$ from both sides:

$4y=2-12x$

Divide $4$ from both sides:

$y=(2-12x)/4$

Simplify:

$y=1/2-3x$

$y=-3x+1/2$

This last equation is now in $y=mx+b$ form where

$m$ is the slope (the coefficient of the variable $x$ )

$b$ is the $y-$ intercept or the constant

From the equation:

$y=-3x+1/2$

Slope $=m=-3$

$y-$ intercept $=b=1/2$

How do you find the slope and intercept of 12x+4y-2=012x+4y-2=0?