How do you find the slope and intercept of $\frac{2}{3} x + \frac{1}{6} y = 2$ $2/3x+1/6y=2$ ?

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Answer 1 · 2016-07-01T01:20:25

Intercept: 12

$\frac{2}{3} x + \frac{1}{6} y = 2$ $2/3x+1/6y=2$ (Subtract $\frac{2}{3} x$ $2/3x$ from both sides)

$\frac{1}{6} y = - \frac{2}{3} x + 2$ $1/6y=-2/3x+2$ (Now multiply both sides by 6)

$y = - 4 x + 12$ $y=-4x+12$

The slope is the coefficient in front of x.(-4)

The intercept is the number with no variable (12)

How do you find the slope and intercept of 23x+16y=22/3x+1/6y=2?