Question

How do you find the slope and intercept of `2x = 1/2y + 2`?

Answer 1

`"slope "=4," y-intercept "=-4`

Explanation:

The equation of a line in `color(blue)"slope-intercept form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))`
where m represents the slope and b, the y-intercept.

`"Rearrange " 2x=1/2y+2" into this form"`

`1/2y+2=2xlarr" reversing the equation"`

subtract 2 from both sides.

`1/2ycancel(+2)cancel(-2)=2x-2`

`rArr1/2y=2x-2`

multiply terms on both sides by 2

`y=4x-4larrcolor(red)" in form y=mx+b"`

`rArr"slope "=m=4" and y-intercept "=b=-4`
graph{4x-4 [-10, 10, -5, 5]}