How do you find the slope and intercept of $-2x - 3y = 1$ ?

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Answer 1 · 2016-01-18T23:45:07

We can convert to the slope intercept form, $y=mx +b$ by isolating $y$ , and then read the slope ( $m$ ) and intercept ( $b$ ) from the equation.

We can isolate $y$ by first moving the $x$ term, and then eliminating the coefficient of $y$

$-2x-3y=1$

We can move the x term by adding $2x$ to both sides:

$cancel(2x)- cancel(2x)-3y=1+2x$

and clear the $y$ coefficient by dividing both sides by $-3$

$(cancel(-3)y)/cancel(-3)=(1+2x)/-3$

and then we can tity and rearrange to get our slope-intercept form:

$y=-2/3x-1/3$

So the slope and intercept are $-2/3$ and $-1/3$ , respectively.

How do you find the slope and intercept of -2x - 3y = 1-2x - 3y = 1?