How do you find the slope and intercept of $2 x - 3 y = 6$ $2x-3y=6$ ?

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Answer 1 · 2016-01-05T10:00:40

# slope = 2/3 and intercept = -2

begin by rewriting the equation in the form y = mx + c where m = slope and c = intercept

so 2x - 3y = 6 ( and rewriting gives)
-3y = -2x + 6 ( now divide all terms by -3)

# (-3y)/-3 =( -2x)

and y = $(\frac{2}{3}) x - 2$ $(2/3) x - 2$

hence $m = \frac{2}{3} and$ $m = 2/3 and$ intercept = - 2

How do you find the slope and intercept of 2x−3y=62x-3y=6?