How do you find the slope and intercept of 2x-5y= -102x−5y=−10?

1 Answer
Deepak G.
Jul 25, 2016

xx-intercept is x=-5x=−5

yy-intercept is y=2y=2

slope=2/525

Explanation:

2x-5y=-102x−5y=−10
xx-intercept is when y=0y=0
So by putting y=0y=0 in the above equation we get
2x-5(0)=-102x−5(0)=−10
or
2x-0=-102x−0=−10
or
2x=-102x=−10
or
x=-10/2x=−102
or
x=-5x=−5 --------------Ans 11

yy-intercept is when x=0x=0
So by putting x=0x=0 in the equation 2x-5y=-102x−5y=−10 we get
2(0)-5y=-102(0)−5y=−10
or
0-5y=-100−5y=−10
or
-5y=-10−5y=−10
or
5y=105y=10
or
y=10/5y=105
y=2y=2 --------------Ans 22

In the equation y=mx+c; my=mx+c;m is the slope
So we can rewrite equation 2x-5y=-102x−5y=−10
as
5y=2x+105y=2x+10
or
y=(2/5)x+10/5y=(25)x+105
or
y=(2/5)x+2y=(25)x+2

Hence slope=2/525 ----------Ans 33

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