How do you find the slope and intercept of $3/2x+y=-5$ ?

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Answer 1 · 2016-01-10T19:14:46

slope = $-3/2$ , y-intercept = -5

One of the forms of the equation of a straight line is y = mx + c

where m represents the slope and c the y-intercept.

rearranging the given equation into this form : $y = -3/2 x - 5$

comparing the two equations we get that m = $-3/2$ and y-intercept is -5.

How do you find the slope and intercept of 3/2x+y=-53/2x+y=-5?