How do you find the slope and intercept of $3 x - 2 y = - 6$ $3x-2y= -6$ ?

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How do you find the slope and intercept of $3 x - 2 y = - 6$ $3x-2y= -6$ ?

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Answer 1 · 2016-07-07T20:41:22

The slope is $\frac{3}{2}$ $3/2$ the intercept is $3$ $3$ .

Explanation:

To find the slope and the intercept you have to put the equation in the form $y = m x + q$ $y=mx+q$ , then $m$ $m$ is the slope and $q$ $q$ is the intercept.

The first step is to keep the term with the $y$ $y$ on the left and the others on the right

$3 x - 2 y = - 6$ $3x-2y=-6$

$- 2 y = - 3 x - 6$ $-2y=-3x-6$

and now we divide for the coefficient of $y$ $y$ that is $- 2$ $-2$

$y = \frac{3}{2} x + \frac{6}{2}$ $y=3/2x+6/2$

$y = \frac{3}{2} x + 3$ $y=3/2x+3$

The slope is $\frac{3}{2}$ $3/2$ the intercept is $3$ $3$ .

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How do you find the slope and intercept of $3 x - 2 y = - 6$ $3x-2y= -6$ ?

1 Answer

Explanation:

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How do you find the slope and intercept of $3 x - 2 y = - 6$ $3x-2y= -6$ ?