How do you find the slope and intercept of $3 x + 4 y - 16 = 0$ $3x+4y-16=0$ ?

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How do you find the slope and intercept of $3 x + 4 y - 16 = 0$ $3x+4y-16=0$ ?

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Answer 1 · 2016-01-21T23:16:16

I found: $m = - \frac{3}{4}$ $m=-3/4$

Explanation:

You can try to write it in Slope-Intercept form:
$y = m x + c$ $y=mx+c$
where $m$ $m$ will be the slope.

We isolate $y$ $y$ on one side:
$4 y = - 3 x + 16$ $4y=-3x+16$
$y = - \frac{3}{4} x + 4$ $y=-3/4x+4$
so that the slope will be $m = - \frac{3}{4}$ $m=-3/4$

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How do you find the slope and intercept of $3 x + 4 y - 16 = 0$ $3x+4y-16=0$ ?

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Explanation:

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How do you find the slope and intercept of $3 x + 4 y - 16 = 0$ $3x+4y-16=0$ ?