How do you find the slope and intercept of $3 x + 4 y = 7$ $3x+4y=7$ ?

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Answer 1 · 2015-12-30T11:29:57

slope = $- \frac{3}{4}$ $-3/4$
y intercept = $\frac{7}{4}$ $7/4$

3x + 4y = 7
4y = -3x +7
y = $- \frac{3}{4}$ $-3/4$ x + $\frac{7}{4}$ $7/4$

comparing with y=mx+c
we get,
m= slope = $- \frac{3}{4}$ $-3/4$

c = y intercept = $\frac{7}{4}$ $7/4$

3x +4y = 7

$\frac{3}{7}$ $3/7$ x + $\frac{4}{7}$ $4/7$ y = $\frac{7}{7}$ $7/7$

$\frac{3}{7}$ $3/7$ x + $\frac{4}{7}$ $4/7$ y = 1

$\frac{x}{\frac{7}{3}}$ $x/ (7/3)$ + $\frac{y}{\frac{7}{4}}$ $y/ (7/4)$ = 1

comparing with $\frac{x}{a}$ $x/a$ + $\frac{y}{b}$ $y/b$ = 1
we get,
x intercept = $\frac{7}{3}$ $7/3$
y intercept = $\frac{7}{4}$ $7/4$

How do you find the slope and intercept of 3x+4y=73x+4y=7?