How do you find the slope and intercept of $−3x − 5y + 35 = 0$ ?

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Answer 1 · 2016-08-18T12:48:04

$m = -3/5 and c = 7$

Change this equation of a straight line into slope-intercept form which is $y = mx +c$

$5y = -3x+35 " isolate the y term"$

$y = -3/5x +7" "div 5$

Now you can see that $m = -3/5 and c = 7$

How do you find the slope and intercept of −3x − 5y + 35 = 0−3x − 5y + 35 = 0?