How do you find the slope and intercept of $- 3 x - 5 y + 35 = 0$ $−3x − 5y + 35 = 0$ ?

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Answer 1 · 2016-08-18T12:48:04

$m = - \frac{3}{5} and c = 7$ $m = -3/5 and c = 7$

Change this equation of a straight line into slope-intercept form which is $y = m x + c$ $y = mx +c$

$5 y = - 3 x + 35 isolate the y term$ $5y = -3x+35 " isolate the y term"$

$y = - \frac{3}{5} x + 7 \div 5$ $y = -3/5x +7" "div 5$

Now you can see that $m = - \frac{3}{5} and c = 7$ $m = -3/5 and c = 7$

How do you find the slope and intercept of −3x−5y+35=0−3x − 5y + 35 = 0?