How do you find the slope and intercept of $3 x + 7 y = 4$ $3x+7y=4$ ?

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How do you find the slope and intercept of $3 x + 7 y = 4$ $3x+7y=4$ ?

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Answer 1 · 2015-10-31T12:46:51

You change the equation into slope-intercept form ( $y = m x + b$ $y=mx+b$ ).

Explanation:

$3 x + 7 y = 4$ $3x+7y=4$
You need to isolate the y by subtracting $3 x$ $3x$ from each side.
$7 y = 4 - 3 x$ $7y=4-3x$
Then, to get rid of the $7 y$ $7y$ and make it a single $y$ $y$ , you divide each side by seven.
$y = \frac{4 - 3 x}{7}$ $y=(4-3x)/7$
You divide four by seven, and three x by seven.
$y = \frac{4}{7} - \frac{3}{7} x$ $y=4/7-3/7x$
Move the $4 x$ $4x$ to have the equation in $y = m x + b$ $y=mx+b$ form.
$y = - \frac{3}{7} x + \frac{4}{7}$ $y=-3/7x+4/7$
The slope is $- \frac{3}{7}$ $-3/7$ and the y-intercept is $\frac{4}{7}$ $4/7$ .

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How do you find the slope and intercept of $3 x + 7 y = 4$ $3x+7y=4$ ?

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