How do you find the slope and intercept of $- 3 x - 8 y + 6 = 0$ $-3x-8y+6=0$ ?

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Answer 1 · 2015-12-15T04:22:25

Slope-Intercept Form:
$y = m x + b$ $y=mx+b$
Where $m$ $m$ is the slope and $b$ $b$ is the y-intercept.

Original Equation:
$- 3 x - 8 y + 6 = 0$ $-3x-8y+6=0$

To put an equation into slope-intercept form, you have to isolate $y$ $y$ . This means you have to get $y$ $y$ by itself:

$- 3 x - 8 y + 6 = 0$ $-3x-8y+6=0$

$- 3 x - 8 y = - 6$ $-3x-8y=-6$

$- 8 y = 3 x - 6$ $-8y=3x-6$

$y = \frac{3 x - 6}{- 8}$ $y=(3x-6)/(-8)$

$y = (- \frac{3}{8}) x + (\frac{3}{4})$ $y=(-3/8)x+(3/4)$

Once you have $y$ $y$ by itself, all you have to do is determine which number is your slope and which is your intercept.

You should end up with:
$m$ $m$ (slope) $= (- \frac{3}{8})$ $=(-3/8)$
and
$b$ $b$ (y-intercept) $= (\frac{3}{4})$ $=(3/4)$

How do you find the slope and intercept of −3x−8y+6=0-3x-8y+6=0?