How do you find the slope and intercept of #3y+5=0#?

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Answer 1 · 2018-03-27T17:46:39

slope #= 0; " " y-"intercept" = (0, -5/3)#

Given: #3y + 5 = 0#

Solve for #y#:
# " "3y = -5#

#" " y = -5/3#

A line has the form: #y = mx + b#;

where #m# = slope, and #b# is the #y#-intercept: #(0, b)#

In the line equation #y = -5/3#; #" "m = 0#

This means the line is a horizontal line at #y = -5/3#

The #y#-intercept #= (0, -5/3)#