How do you find the slope and intercept of $3y+5=0$ ?

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Answer 1 · 2018-03-27T17:46:39

slope $= 0; " " y-"intercept" = (0, -5/3)$

Given: $3y + 5 = 0$

Solve for $y$ :
$" "3y = -5$

$" " y = -5/3$

A line has the form: $y = mx + b$ ;

where $m$ = slope, and $b$ is the $y$ -intercept: $(0, b)$

In the line equation $y = -5/3$ ; $" "m = 0$

This means the line is a horizontal line at $y = -5/3$

The $y$ -intercept $= (0, -5/3)$

How do you find the slope and intercept of 3y+5=03y+5=0?