How do you find the slope and intercept of $4 x - \frac{1}{3} y = - 2$ $4x - 1/3y = -2$ ?

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Answer 1 · 2018-04-10T19:07:32

See explanation.

To find slope and $Y$ $Y$ intercept you have to write the linear function in a form

$y = a x + b$ $y=ax+b$

Here you get:

$4 x - \frac{1}{3} y = - 2$ $4x-1/3y=-2$

$- \frac{1}{3} y = - 4 x - 2$ $-1/3y=-4x-2$

$y = 12 x + 6$ $y=12x+6$

When the function is in the form $y = a x + b$ $y=ax+b$ we can write that:

In the given function we have: