How do you find the slope and intercept of $4 x - \frac{1}{3} y = - 2$ $4x-1/3y=-2$ ?

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Answer 1 · 2016-01-26T10:40:20

$m = 12$ $m=12$ and $b = 6$ $b=6$ .

The equation of a line in slope-intercept form is $y = m x + b$ $y=mx+b$ , where $m$ $m$ is the slope and $b$ $b$ is the y-intercept.

$4 x - \frac{1}{3} y = - 2$ $4x-1/3y=-2$

To convert this equation to slope-intercept form, solve for $y$ $y$ .

Subtract $4 x$ $4x$ from both sides.

$- \frac{1}{3} y = - 2 - 4 x$ $-1/3y=-2-4x$

Simplify $- \frac{1}{3} y$ $-1/3y$ to $- \frac{y}{3}$ $-y/3$

$- \frac{y}{3} = - 2 - 4 x$ $-y/3=-2-4x$

Multiply both sides times $3$ $3$ .

$- y = - 2 (3) - 4 x (3)$ $-y=-2(3)-4x(3)$

Simplify.

$- y = - 6 - 12 x$ $-y=-6-12x$

Rearrange the right side.

$- y = - 12 x - 6$ $-y=-12x-6$

Multiply both sides times $- 1$ $-1$ .

$y = 12 x + 6$ $y=12x+6$

$m = 12$ $m=12$ and $b = 6$ $b=6$ .

How do you find the slope and intercept of 4x−13y=−24x-1/3y=-2?