How do you find the slope and intercept of $4x-3y-7=0$ ?

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Answer 1 · 2016-01-30T08:17:11

This answer involves rearranging the equation to make $y$ the subject.

The slope $m=4/3$ and the y-intercept $b=7/3$ .

$y=mx+b$ where $m$ is the slope and $b$ is the y-intercept

In this case it is simply the algebra of rearranging $4x-3y-7=0$ to make $y$ the subject:

$4x-3y-7=0$ (add 7 to both sides)
$4x-3y=7$ (subtract $4x$ from both sides)
$-3y=7-4x$ (divide both sides by $-3$ )
$y=-(7-4x)/3 =4/3x-7/3$

From the rearranged equation the slope $m=4/3$ and the y-intercept $b=7/3$ .

How do you find the slope and intercept of 4x-3y-7=04x-3y-7=0?