How do you find the slope and intercept of $4x+8y = -64$ ?

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Answer 1 · 2016-01-12T19:29:29

If $Ax+By+C=0$
Then $Slope=-A/B$ , x-intercept $=-C/A$ and y-intercept $=-C/B$ .

$4x+8y=-64$
$implies 4x+8y+64=0$
$implies x+2y+16=0$

Here $A=1, B=2 and C=16$

$implies Slope=-1/2$ , x-intercept $=-16/1=-16$ and y-intercept $=-16/2=-8$

$implies Slope=-1/2$ , x-intercept $=-16$ and y-intercept $=-8$

How do you find the slope and intercept of 4x+8y = -64 4x+8y = -64 ?