How do you find the slope and intercept of $5 (x - 3 y) = 2 (x + 3)$ $5(x-3y)=2(x+3)$ ?

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How do you find the slope and intercept of $5 (x - 3 y) = 2 (x + 3)$ $5(x-3y)=2(x+3)$ ?

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Answer 1 · 2016-08-29T03:33:53

Slope of the line is $\frac{1}{5}$ $1/5$ and intercept on $y$ $y$ -axis is $- \frac{2}{5}$ $-2/5$

Explanation:

The equation of a line in slope intercept form is $y = m x + c$ $y=mx+c$ , where $y$ $y$ is expressed in terms of $x$ $x$ and then $m$ $m$ , the coefficient of $x$ $x$ , is slope and $c$ $c$ the constant term is the value of intercept made by the line on $y$ $y$ -axis.

In the equation $5 (x - 3 y) = 2 (x + 3)$ $5(x-3y)=2(x+3)$ , we simplify and write $y$ $y$ in terms of $x$ $x$ .

$5 (x - 3 y) = 2 (x + 3)$ $5(x-3y)=2(x+3)$

$\Leftrightarrow 5 x - 15 y = 2 x + 6$ $hArr5x-15y=2x+6$ or

$- 15 y = 2 x - 5 x + 6$ $-15y=2x-5x+6$ or

$- 15 y = - 3 x + 6$ $-15y=-3x+6$ or

$y = \frac{- 3}{- 15} x + \frac{6}{- 15}$ $y=(-3)/(-15)x+6/(-15)$ or

$y = \frac{1}{5} x - \frac{2}{5}$ $y=1/5 x-2/5$

Hence slope of the line is $\frac{1}{5}$ $1/5$ and intercept on $y$ $y$ -axis is $- \frac{2}{5}$ $-2/5$ .

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How do you find the slope and intercept of $5 (x - 3 y) = 2 (x + 3)$ $5(x-3y)=2(x+3)$ ?

1 Answer

Explanation:

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How do you find the slope and intercept of 5(x-3y)=2(x+3)5(x−3y)=2(x+3)5(x-3y)=2(x+3)?

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Explanation:

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How do you find the slope and intercept of $5 (x - 3 y) = 2 (x + 3)$ $5(x-3y)=2(x+3)$ ?