How do you find the slope and intercept of 5x-2=05x2=0?

1 Answer
Dec 27, 2015

The slope of (5x-2=0)(5x2=0) is undefined.
It has an x-intercept at x=2/5x=25.
It does not have a y-intercept.

Explanation:

5x-2=05x2=0 is the equation of a vertical line.
It could also be written as x=2/5x=25

Slope is defined as the change in yy divided by a corresponding change in xx
...but since xx is a constant, the change in xx is always 00
so any attempt to calculate the slope results in an attempt to divide by 00.

5x-2=05x2=0 crosses the X-axis at x=2/5x=25 (the x-intercept)
but it does not cross the Y-axis (there is no y-intercept).