How do you find the slope and intercept of 5y-4x+10=05y−4x+10=0?

2 Answers
Jim G.
Apr 29, 2018

"slope "=4/5," y-intercept "=-2slope =45, y-intercept =−2

Explanation:

"the equation of a line in "color(blue)"slope-intercept form"the equation of a line in slope-intercept form is.

•color(white)(x)y=mx+b∙xy=mx+b

"where m is the slope and b the y-intercept"where m is the slope and b the y-intercept

"rearrange "5y-4x+10=0" into this form"rearrange 5y−4x+10=0 into this form

"add 4x and subtract 10 from both sides"add 4x and subtract 10 from both sides

rArr5y=4x-10⇒5y=4x−10

"divide all terms by 5"divide all terms by 5

rArry=4/5x-2larrcolor(blue)"in slope-intercept form"⇒y=45x−2←in slope-intercept form

"with slope "=4/5" and y-intercept "=-2with slope =45 and y-intercept =−2

Sayuri <3 · Stefan V.
Apr 29, 2018

See below:

Explanation:

The equation of the line is

5y-4x=-105y−4x=−10

5y=4x -105y=4x−10

So

y= (4x)/5 - 10/5y=4x5−105

y=4/5x-2y=45x−2

This is in the form of

y=mx+cy=mx+c

where;

  • yy-intercept (c)=-2(c)=−2
  • slope (m)=4/5(m)=45

Hope this will help you :)

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