Question

How do you find the slope and intercept of `6y+6 = 0`?

Answer 1

The slope is `0`.

There is no `x`-intercept.

The `y`-intercept is at `(0, -1)`.

Explanation:

`6y + 6 = 0`

First, make `y` by itself. Subtract `color(blue)6` from both sides:
`6y + 6 quadcolor(blue)(-quad6) = 0 quadcolor(blue)(-quad6)`

`6y = -6`

Divide both sides by `color(blue)6`:
`(6y)/color(blue)6 = (-6)/color(blue)6`

`y = -1`

When the equation is `y` equals to a number constant, that means it is a horizontal slope, or it has a slope of `0`.

There is no `x`-intercept since the equation never touches the `x`-axis. The `y`-intercept would be at `(0, -1)`, since whatever `x`-value you put into the equation does nothing. The equation is a constant, and it is always where `y = -1`.

Hope this helps!