Question

How do you find the slope and intercept of `7x + 3y=4`?

Answer 1

`-7/3` & `4/3`

Explanation:

Given that

`7x+3y=4`

`3y=-7x+4`

`y=-7/3x+4/3`

Comparing above equation with the slope-intercept form of straight line: `y=mx+c` we get

Slope: `m=-7/3`

y-Intercept: `c=4/3`

Answer 2

Slope= `-7/3`

`y`-intercept= `4/3`

Explanation:

We can find the `y`-intercept by setting `x` to zero, because that is exactly what the `y`-intercept means...when `x=0` we are on the `y` axis.

If we set `x` to zero, that term disappears, and we are left with

`3y=4=>y=4/3`

This is our `y`-intercept.

To go about finding our slope, we can convert this equation into slope-intercept form

`y=mx+b` where `m` is the slope and `b` is the `y`-intercept.

`7x+3y=4`

We want just a `y` on the left, so we can subtract `7x` from both sides to get

`3y=-7x+4`

Dividing all terms by `3`, we get

`y=-7/3x+4/3`

Our slope is the coefficient on `x`, which in our case, is `-7/3`.

The `y`-intercept is the constant and we see that this is `4/3`.

Hope this helps!