How do you find the slope and intercept of $7x=5y$ ?

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Answer 1 · 2018-05-25T02:19:33

The slope is $7/5$ and the y-intercept is $0$ .

Reverse the equation.

$5y=7x$

Divide both sides by $5$ .

$y=7/5x$

This equation is in slope-intercept form:

$y=mx+b$ ,

where $m$ is the slope, and $b$ is the y-intercept.

In the equation $y=7/5x$ , the slope is $7/5$ and the y-intercept is $0$ .

graph{y=7/5x [-10, 10, -5, 5]}

Answer 2 · 2018-05-25T02:25:06

Slope: $7/5$ , Intercepts $(0,0)$

$7x = 5y -> y=7/5x$

Recall the equation of a straight line in slope $(m)$ and $y-$ intercept $(c)$ form is: $y=mx+c$

In this example: $m=7/5 and c=0$

Also, $x=0$ where $y=0$

Hence, $y$ is a straight line through the origin with slope $7/5$ as shown below.

graph{7/5x [-11.46, 11.04, -4.785, 6.465]}

So, slope of $y$ is $7/5$ and both $x and y$ Intercepts occur at the point $(0,0)$

How do you find the slope and intercept of 7x=5y7x=5y?