How do you find the slope and intercept of $8x-1/2y=-2$ ?

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Answer 1 · 2016-09-11T16:17:21

$8x-1/2y=-2$

Solve for y

$-1/2y=-8x-2$

$y=16x+4$

Slope-intercept form: $y=mx+b$ , m=slope, b=y-intercept

Slope=16, y-intercept= $(0,4)$

x-intercept: let y=0

$0=16x+4$

$-4=16x$

$-1/4=x$

x-intercept= $(-1/4,0)$

How do you find the slope and intercept of 8x-1/2y=-28x-1/2y=-2?