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How do you find the slope and intercept of $\frac{x + 1}{2} + \frac{y + 1}{2} = 1$ $(x+1)/2 + (y+1)/2 = 1$ ?

1 Answer

May 18, 2018

Slope: $(- 1)$ $(-1)$
y-intercept: $0$ $0$

Explanation:

Given $\frac{x + 1}{2} + \frac{y + 1}{2} = 1$ $(x+1)/2+(y+1)/2=1$

We can multiply everything (on both sides) by $2$ $2$ to get an equivalent equation:
$XXX (x + 1) + (y + 1) = 2$ $color(white)("XXX")(x+1)+(y+1)=2$

Simplifying:
$XXX x + y + 2 = 2$ $color(white)("XXX")x+y+2=2$

$XXX y = - x$ $color(white)("XXX")y=-x$

or, in slope intercept form:
$XXX y = (- 1) x + 0$ $color(white)("XXX")y=color(green)(""(-1))x+color(red)0$
with slope $= (_1)$ $=color(green)(""(_1))$ and y-intercept $0$ $color(red)0$

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