How do you find the slope and intercept of $x + 2 y = 3$ $x + 2y=3$ ?

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Answer 1 · 2016-02-24T19:48:03

Rearrange the equation to get $m = - \frac{1}{2}, b = \frac{3}{2}$ $m=-1/2 , b=3/2$

The slope-intercept form of a line is given by

$y = m x + b$ $y=mx+b$

where $m$ $m$ is the slope and $b$ $b$ is the y-intercept. Our equation needs to be rearranged into this form. We are starting with:

$x + 2 y = 3$ $x+2y=3$

First, we'll move the $x$ $x$ to the other side (by subracting $x$ $x$ from both sides):

$2 y = - x + 3$ $2y=-x+3$

Now we divide both sides of the equation by $2$ $2$ to get $y$ $y$ all by itself:

$y = - \frac{1}{2} x + \frac{3}{2}$ $y=-1/2 x+3/2$

By comparing this equation to the slope intercept form we can see that

$m = - \frac{1}{2}, b = \frac{3}{2}$ $m=-1/2 , b=3/2$

How do you find the slope and intercept of x+2y=3x + 2y=3?