How do you find the slope and intercept of $x + 4 y = - \frac{1}{2}$ $x+4y = -1/2$ ?

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Answer 1 · 2016-06-27T20:37:28

$m = - \frac{1}{4}, c = - \frac{1}{8}$ $m= -1/4, c= -1/8$

Change the equation into $y = m x + c$ $y = mx +c$

$4 y = - x - \frac{1}{2} divide by 4$ $4y = -x -1/2 " divide by 4"$

$y = - \frac{1}{4} x - \frac{1}{8}$ $y = -1/4x -1/8$

How do you find the slope and intercept of x+4y = -1/2x+4y=−12x+4y = -1/2?