How do you find the slope and intercept of $x - y = 2$ $x- y=2$ ?

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Answer 1 · 2018-06-02T07:56:57

$slope = 1$ $"slope "=1$

$intercept = - 2$ $"intercept "=-2$

rearrange to the form $y = m x + c$ $y=mx+c$

$x - y = 2$ $x-y=2$

$\Rightarrow y = x - 2$ $=>y=x-2$

$m =$ $m=$ gradient/slope

$:. "slope "=1$

$c="intercept"$

$"intercept "=-2$

as shown on the graph

graph{x-y=2 [-10, 10, -5, 5]}

Answer 2 · 2018-06-02T07:58:35

the slope is $1$ and the intercepts are $y=-2$ and $x=2$

Writing your equation in the form
$y=x-2$
we get the slope of $1$
and
$P_1(0;-2)$
and
$P_2(2;0)$

How do you find the slope and intercept of x- y=2x−y=2x- y=2?