How do you find the slope and intercept of y= -2/5x + 20y=−25x+20?

2 Answers
Jim G.
May 17, 2018

"slope "=-2/5," y-intercept "=20slope =−25, y-intercept =20

Explanation:

"the equation of a line in "color(blue)"slope-intercept form"the equation of a line in slope-intercept form is.

•color(white)(x)y=mx+b∙xy=mx+b

"where m is the slope and b the y-intercept"where m is the slope and b the y-intercept

y=-2/5x+20" is in this form"y=−25x+20 is in this form

"with slope "=-2/5" and y-intercept "=20with slope =−25 and y-intercept =20

Mohit · Stefan V.
May 17, 2018

Slope = -2/5=−25

yy-intercept = 20=20

Explanation:

The given equation is the standard slope-intercept form of a straight line equation,

y = mx + cy=mx+c

where

  • m =m= slope ->→ tangent of the angle made by the straight line intercepting one of the axes (xx or yy)
  • c =c= the yy-intercept, which remains constant.

Thus putting your equation in accordance with the standard equation, the slope is -2/5−25 and the yy-intercept is 2020.

graph{y = -2/5x + 20 [-80, 80, -40, 40]}

Since the slope is negative in magnitude, the tangent of the angle is greater than 180^@180∘ and hence, the straight line cuts the positive xx axis. Otherwise, in case of a positive slope, the straight line only cuts the positive yy axis, thus giving us the intercept.

Here the straight line cuts the positive yy axis at (0,20)(0,20) and hence the yy-intercept is 2020.

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