How do you find the slope and intercept of $y = - 3 x$ $y=-3x$ ?

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Answer 1 · 2016-03-27T20:25:28

Slope = -3
$x_{intercept} = 0$ $x_("intercept") =0$
$y_{intercept} = 0$ $y_("intercept")=0$

Consider the standard form of $y = m x + c$ $y=mx+c$

This is the equation of a straight line that passes through the origin.

In your case $c = 0$ $c=0$ so $y_{intercept} = c = 0$ $" "y_("intercept")=c=0$

$x_{intercept}$ $x_("intercept")$ occurs at $y = 0$ $y=0$

So as $0 = m x$ $0=mx$ it means that as $m \neq 0 then x = 0$ $m!=0" then "x=0$

#x_("intercept") =0

The gradient is m =-3

How do you find the slope and intercept of y=−3xy=-3x?