How do you find the slope and intercept of #y=-3x#?

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Answer 1 · 2016-03-27T20:25:28

Slope = -3
#x_("intercept") =0#
#y_("intercept")=0#

Consider the standard form of #y=mx+c#

This is the equation of a straight line that passes through the origin.

In your case #c=0# so #" "y_("intercept")=c=0#

#x_("intercept") # occurs at #y=0#

So as #0=mx# it means that as #m!=0" then "x=0#

#x_("intercept") =0

The gradient is m =-3