How do you find the slope and intercept of $y = 3 x - 2$ $y = 3x -2$ ?

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Answer 1 · 2016-07-15T15:33:55

Slope = 3, y-intercept = -2, x-intercept = $\frac{2}{3}$ $2/3$

If an equation of a straight line is given in the standard form as

$y - m x + c$ $y - mx +c$ ,

then we have the slope and the y-intercept immediately.

In $y = 3 x - 2$ $y = 3x -2$ , we have $m = 3 and c = - 2$ $m = 3 and c = -2$

To find the x-intercept, make $y = 0$ $y=0$

$0 = 3 x - 2 \Rightarrow x = \frac{2}{3}$ $0 = 3x -2 rArr x = 2/3$

How do you find the slope and intercept of y = 3x -2y=3x−2y = 3x -2?