How do you find the slope and intercept of #y = 6x + 1#?

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Answer 1 · 2018-03-25T19:21:22

m = #6#

x-intercept = #(-1/6,0)#

y-intercept = #(0,1)#

#color(blue)"Slope"# = #color(blue){(rise)/(run)}#
Since 6 is essentially #6/1# we know that the slope goes up 6 units

and right 1 unit on a graph.

Next, #color(blue)"to find the y-intercept"# of y=6x+1, you substitute x as x=0."#

#y=6x+1#

#y=6(0)+1#

#y=1#

#:.# the y-intercept is 1 when x is 0 thus #(0,1)#

#color(blue)"To find the x-intercept"# of y=6x+1, you let y=0.

#y=6x+1#

#0=6x+1#

#0-1=6x#

#-1=6x#

#x=-1/6#

#:.# the x-intercept is -1/6 when y is 0 thus #(-1/6,0)#

graph{6x+1 [-10, 10, -5, 5]}