How do you find the slope and the intercepts of $3 x - 4 y = 12$ $3x-4y=12$ ?

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How do you find the slope and the intercepts of $3 x - 4 y = 12$ $3x-4y=12$ ?

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Answer 1 · 2015-05-25T20:52:15

I would try rearranging your equation by isolating $y$ $y$ on the left as:
$y = \frac{3}{4} x - \frac{12}{4}$ $y=3/4x-12/4$
$y = \frac{3}{4} x - 3$ $y=3/4x-3$
So now you can "read" the information from your equation:
slope= $\frac{3}{4}$ $3/4$
y-intercept= $- 3$ $-3$ (for $x = 0$ $x=0$ )
x-intercept= $4$ $4$ (for $y = 0$ $y=0$ )

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How do you find the slope and the intercepts of $3 x - 4 y = 12$ $3x-4y=12$ ?

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How do you find the slope and the intercepts of $3 x - 4 y = 12$ $3x-4y=12$ ?