How do you find the slope and the y-intercept of the line represented by the equation: $-3x + 4y = 8$ ?

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Answer 1 · 2018-05-07T00:01:19

Refer to explanation

First, rewrite the equation in the form, $y=mx+c$ .

$4y-3x = 8$

$4y = 3x+8$

$y= 3/4x +2$

The gradient of the line is the the coefficient of x.

$dy/dx = 3/4$

To calculate the $y$ intercept, you make $x=0$ .

$y = 3/4 (0) +2$

$y = 2$

How do you find the slope and the y-intercept of the line represented by the equation: -3x + 4y = 8-3x + 4y = 8?