How do you find the slope and y intercept for $- 4 x + 5 y = 10$ $-4x + 5y = 10$ ?

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Answer 1 · 2015-05-26T12:34:17

The slope- (y) intercept form is
$y = m x + b$ $y = mx +b$
So we need to re-arrange $- 4 x + 5 y = 10$ $-4x+5y = 10$ into this form

$5 y = 4 x + 10$ $5y = 4x+10$

$y = \frac{4}{5} x + 2$ $y = 4/5x +2$

The slope is $\frac{4}{5}$ $4/5$
and the y-intercept is $2$ $2$

How do you find the slope and y intercept for −4x+5y=10-4x + 5y = 10?