How do you find the slope and y-intercept for the line $x - 4 y = 40$ $x - 4y = 40$ ?

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Answer 1 · 2015-09-23T04:30:39

The slope is $\frac{1}{4}$ $1/4$ , and the y-intercept is $- 10$ $-10$ .

Solve the equation for $y$ $y$ .

$x - 4 y = 40$ $x-4y=40$

Subtract $x$ $x$ from both sides of the equation.

$- 4 y = 40 - x$ $-4y=40-x$

Divide both sides by $- 4$ $-4$ .

$y = \frac{40}{- 4} - \frac{x}{- 4} =$ $y=40/(-4)-x/(-4)=$

$y = - 10 + \frac{x}{4}$ $y=-10+x/4$

$\frac{x}{4} = \frac{1}{4} x$ $x/4=1/4x$ .

Rewrite the equation.

$y = \frac{1}{4} x - 10$ $y=1/4x-10$

The slope is $\frac{1}{4}$ $1/4$ , and the y-intercept is $- 10$ $-10$ .

graph{y=1/4x-10 [-11.34, 8.66, -13.79, -3.79]}

How do you find the slope and y-intercept for the line x−4y=40x - 4y = 40?