How do you find the slope and y-intercept for the line $x + y + 2 = 0$ $x + y + 2 = 0$ ?

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How do you find the slope and y-intercept for the line $x + y + 2 = 0$ $x + y + 2 = 0$ ?

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Answer 1 · 2015-09-24T13:15:51

Slope: $- 1$ $-1$
$y$ $y$ -intercept: $- 2$ $-2$ .

Explanation:

To find the slope and the $y$ $y$ -intercept of a line, you need to put it in the form

$y = m x + q$ $y=mx+q$ .

Then, $m$ $m$ will be the slope and $q$ $q$ the intercept.

In your case, it is very simple, because you only need to isolate the $y$ $y$ , bringing the term $x + 2$ $x+2$ on the right hand, and thus changing its sign into $- x - 2$ $-x-2$ . Once in the form $y = - x - 2$ $y=-x-2$ , you'll have $m = - 1$ $m=-1$ and $q = - 2$ $q=-2$ .

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How do you find the slope and y-intercept for the line $x + y + 2 = 0$ $x + y + 2 = 0$ ?

1 Answer

Explanation:

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How do you find the slope and y-intercept for the line $x + y + 2 = 0$ $x + y + 2 = 0$ ?