How do you find the slope and y intercept for $y = \frac{1}{5} x - 8$ $y=1/5x-8$ ?

Question

5064 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-30T12:53:56

If $y = m x + c$ $y=mx+c$ is an equation of line then $m$ $m$ and $c$ $c$ are said to be its slope and y-intercept respectively.

Here,

$y = \frac{1}{5} x - 8$ $y=1/5x-8$
$\Rightarrow y = \frac{1}{5} x + (- 8)$ $implies y=1/5x+(-8)$ compare $y = m x + c$ $y=mx+c$

$\Rightarrow m = \frac{1}{5} and c = - 8$ $implies m=1/5 and c=-8$

Hence, slope $= \frac{1}{5}$ $=1/5$ and y-intercept $= - 8$ $=-8$

How do you find the slope and y intercept for y=15x−8y=1/5x-8?