How do you find the slope and y intercept for $y = - 2 x + 3$ $y = -2x + 3$ ?

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Answer 1 · 2015-07-11T00:17:40

The slope is $- 2$ $-2$ and the $y$ $y$ -intercept is at ( $0, 3$ $0,3$ ).

The "slope-intercept" form of a straight line equation is

$y = m x + b$ $y = mx + b$ ,

where $m$ $m$ is the slope and $b$ $b$ is the $y$ $y$ -intercept.

Your equation is

$y = - 2 x + 3$ $y = -2x +3$

If we compare the two equations, we see that $m = - 2$ $m = -2$ and $b = 3$ $b = 3$ .

So the slope is $- 2$ $-2$ and the $y$ $y$ -intercept is at ( $0, 3$ $0,3$ ).

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How do you find the slope and y intercept for y = -2x + 3y=−2x+3y = -2x + 3?