How do you find the slope and y-intercept of the graph of 3x-2y+8=0?

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Answer 1 · 2016-07-11T07:03:41

Slope #=3/2#
y- intercept #=4#

Given -

#3x-2y+8=0#

This equation is in the form of

#ax+by+c=0#
Then its slope is defined as #=(-a)/b#

In our case, slope is,

#m=(-a)/b=(-3)/-2=3/2#

Find intercept-

At #x=0; 3(0)-2y+8=0#

#-2y=-8#
#y=(-8)/(-2)=4#