How do you find the slope and y-intercept of the graph of 3x-2y+8=0?

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Answer 1 · 2016-07-11T07:03:41

Slope $= \frac{3}{2}$ $=3/2$
y- intercept $= 4$ $=4$

Given -

$3 x - 2 y + 8 = 0$ $3x-2y+8=0$

This equation is in the form of

$a x + b y + c = 0$ $ax+by+c=0$
Then its slope is defined as $= \frac{- a}{b}$ $=(-a)/b$

In our case, slope is,

$m = \frac{- a}{b} = \frac{- 3}{- 2} = \frac{3}{2}$ $m=(-a)/b=(-3)/-2=3/2$

Find intercept-

At $x = 0; 3 (0) - 2 y + 8 = 0$ $x=0; 3(0)-2y+8=0$

$- 2 y = - 8$ $-2y=-8$
$y = \frac{- 8}{- 2} = 4$ $y=(-8)/(-2)=4$