How do you find the slope and y-intercept of the line #2x-3y=18#?

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Answer 1 · 2017-01-25T10:41:10

Slope #m=2/3#
Y intercept #(0, -6)#

given -

#2x-3y=18#

The slope of the equation of the form #ax+by=c# is -

#m=(-a)/b=(-2)/(-3)=2/3#

To find the y-intercept put #x=0#

#2(0)-3y=18#
#-3y=18#
#y=18/(-3)=-6#

Slope #m=2/3#
Y intercept #(0, -6)#
graph{2x-3y=18 [-6.58, 13.42, -7.28, 2.72]}