How do you find the slope and y-intercept of the line $2 x - 3 y = 18$ $2x-3y=18$ ?

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Answer 1 · 2017-01-25T10:41:10

Slope $m = \frac{2}{3}$ $m=2/3$
Y intercept $(0, - 6)$ $(0, -6)$

given -

$2 x - 3 y = 18$ $2x-3y=18$

The slope of the equation of the form $a x + b y = c$ $ax+by=c$ is -

$m = \frac{- a}{b} = \frac{- 2}{- 3} = \frac{2}{3}$ $m=(-a)/b=(-2)/(-3)=2/3$

To find the y-intercept put $x = 0$ $x=0$

$2 (0) - 3 y = 18$ $2(0)-3y=18$
$- 3 y = 18$ $-3y=18$
$y = \frac{18}{- 3} = - 6$ $y=18/(-3)=-6$

Slope $m = \frac{2}{3}$ $m=2/3$
Y intercept $(0, - 6)$ $(0, -6)$
graph{2x-3y=18 [-6.58, 13.42, -7.28, 2.72]}

How do you find the slope and y-intercept of the line 2x−3y=182x-3y=18?