How do you find the slope and y intercept of the line that is perpendicular to #y=-x-1# and passes through the point (5, 7)?
1 Answer
Nov 26, 2016
The equation of the line is
The slope is
The intercepts are
Explanation:
The equation of a line is
where
The slope of the line
The slope of the perpedicular line is
So
The equation of a line, that passes through
Here,
So, the equation is
graph{(y+x+1)(y-x-2)=0 [-7.9, 7.9, -3.95, 3.95]}